If a radiograph is produced using 4 milliampere-seconds (mAs) and 70 kilovoltage peak (kVp), and the mAs is changed to 8 while maintaining the same kVp, what will the receptor exposure be?

When evaluating the exposure of a radiographic image based on changes in milliampere-seconds (mAs), it's essential to understand how mAs directly influences receptor exposure. The relationship between mAs and receptor exposure is linear, meaning that doubling the mAs will effectively double the receptor exposure.

In this scenario, the original mAs is 4. When it is increased to 8 mAs, this represents a doubling of the original exposure parameter. If the initial receptor exposure is set at a specific level (let's assume a baseline value for clarification), then doubling the mAs will also double that receptor exposure, resulting in a new exposure that is twice the baseline value.

If the receptor exposure at 4 mAs yields a certain measured value, increasing it to 8 mAs appropriately doubles that measured value. For instance, if the exposure from 4 mAs was 0.001 mGy, doubling it with 8 mAs would lead to a receptor exposure of 0.002 mGy.

Therefore, the answer that reflects this correct relationship—given the information provided—is 0.002 mGy, which aligns with the understanding that increasing mAs directly increases receptor exposure in a predictable manner.